An energy DRONE is flying along the curve y = x2 + 7. A soldier is placed at (3, 7). The nearest distance of the DRONE from soldier’s position is
Answer & explanation
Correct answer: option 3
Let P(x, y) be position of the DRONE and the soldier is placed at A(3, 7).
$AP=\sqrt{(x-3)^2+(y-7)^2}$ .....(i)
$y = x^2 + 7$ .....(ii)
since point lies on the curve
$S=\sqrt{(x-3)^2+(x^2+7-7)^2}$
$S=\sqrt{x^4+x^2-6x+9}$
when distance is maximum/minimum
$\frac{dS}{dx}=0⇒\frac{(4x^3+2x-6)}{\sqrt{(x^4+x^2-6x+9)}}=0$
$⇒4x^3+2x-6=0$
$⇒2x^3+x-3=0$
$⇒(x-1) × (2x^2+2x+3)$
The solution to above equation are
$x = 1, -0.5 ± i × 0.5\sqrt{5}$
Since solution cannot have any complex roots.
Hence, x = 1 is abscissa of the nearest point to the soldier.
from eq. (i) we get,
$y =1^2+7⇒y=8$
Nearest point is (1, 8)
nearest distance $S = \sqrt{(1-3)^2+(8-7)^2}$
$S = \sqrt{(-2)^2+(1)^2}⇒S=\sqrt{4+1}$
$\Rightarrow S=\sqrt{5}$