Find the missing term in given series?
4, 6, 9, \(13\frac{1}{2}\), ?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → \(20\frac{1}{4}\)
Each term is one and a half times the previous term, that is, the previous term multiplied by \(\frac{3}{2}\):
\(\displaystyle 4\times\frac{3}{2}=6\)
\(\displaystyle 6\times\frac{3}{2}=9\)
\(\displaystyle 9\times\frac{3}{2}=\frac{27}{2}=13\frac{1}{2}\)
\(\displaystyle \frac{27}{2}\times\frac{3}{2}=\frac{81}{4}=20\frac{1}{4}\)