CUET Preparation Today
When a radiation is incident on a metal surface of work function ($\phi_0$), photo electrons are emitted with some maximum kinetic energy ($k$). If the frequency of the incident radiation is doubled, then the maximum kinetic energy of the emitted photo electrons will become |
$2 k$ $2k - \phi_0$ $2k + \phi_0$ $k$ |
$2k + \phi_0$ |
The correct answer is Option (3) → $2k + \phi_0$ |
