Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Waves

Question:

If $μ_0$ is the permeability and $ε_0$ is the permittivity of free space, then the velocity of light is

Options:

$\sqrt{\frac{μ_0}{ε_0}}$

$\frac{1}{\sqrt{μ_0ε_0}}$

$\sqrt{\frac{ε_0}{μ_0}}$

$\sqrt{μ_0ε_0}$

Correct Answer:

$\frac{1}{\sqrt{μ_0ε_0}}$

Explanation:

The correct answer is Option (2) → $\frac{1}{\sqrt{μ_0ε_0}}$

The velocity of light in vacuum is related to the permeability and permittivity of free space as:

$c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$