If $μ_0$ is the permeability and $ε_0$ is the permittivity of free space, then the velocity of light is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{1}{\sqrt{μ_0ε_0}}$
The velocity of light in vacuum is related to the permeability and permittivity of free space as:
$c = \frac{1}{\sqrt{\mu_0 \epsilon_0}}$