Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electric Charges and Fields

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

Let electric field is zero at a distane x from -2q charge.

$\frac{K.2q}{4\pi \epsilon_0 x^2} = \frac{K 8q}{4\pi \epsilon_0 (x+L)^2}$

$\Rightarrow (x+L)^2 = 4 x^2$

$\Rightarrow (x+L) = \pm 2x$

$\Rightarrow x = L $

 Distance of point from origin i.e from 8q is 2L.