Let $D$ be the domain of the real valued function $f$ defined by $f(x) = \sqrt{25 - x^2}$. Then, write $D$.

$[ -5, 5 ]$

The correct answer is Option (3) → $[ -5, 5 ]$ ##

Given function, $f(x) = \sqrt{25 - x^2}$

For real valued of $f(x)$, $25 - x^2 \ge 0$

$x^2 \le 25$ [on multiplying in inequality by $-ve$ sign, then sign of inequality will change]

$-5 \le x \le +5$

$∴D = [-5, 5]$