Let $D$ be the domain of the real valued function $f$ defined by $f(x) = \sqrt{25 - x^2}$. Then, write $D$.
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $[ -5, 5 ]$ ##
Given function, $f(x) = \sqrt{25 - x^2}$
For real valued of $f(x)$, $25 - x^2 \ge 0$
$x^2 \le 25$ [on multiplying in inequality by $-ve$ sign, then sign of inequality will change]
$-5 \le x \le +5$
$∴D = [-5, 5]$