In what ratio must a grocer mix two varieties of tea worth ₹180 per kg and ₹200 per kg respectively so that selling the mixture at ₹216.20, he may gain 15%

3 : 2

The correct answer is option (3) : 3 : 2

Let the C.P of mixture be Z x /kg

$S.P=C.P+profit$

$216.20= x + 15$% of x

$216.20= \frac{115x}{100}$

$x=\frac{21620}{115}$

$x= 188$

Given $c= ₹180/kg$

$d= ₹200/kg$

$m= ₹188/kg$

$\frac{\text{quantity of cheaper tea}}{\text{quantity of dearer tea}}=\frac{200-188}{188-180}$

$=\frac{12}{8}=\frac{3}{2}$

Hence the required ratio $=3: 2$