In what ratio must a grocer mix two varieties of tea worth ₹180 per kg and ₹200 per kg respectively so that selling the mixture at ₹216.20, he may gain 15%
Answer & explanation
Correct answer: option 3
The correct answer is option (3) : 3 : 2
Let the C.P of mixture be Z x /kg
$S.P=C.P+profit$
$216.20= x + 15$% of x
$216.20= \frac{115x}{100}$
$x=\frac{21620}{115}$
$x= 188$
Given $c= ₹180/kg$
$d= ₹200/kg$
$m= ₹188/kg$
$\frac{\text{quantity of cheaper tea}}{\text{quantity of dearer tea}}=\frac{200-188}{188-180}$
$=\frac{12}{8}=\frac{3}{2}$
Hence the required ratio $=3: 2$