If A and B are invertible matrices of the same order, then
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $(AB)^{-1}=B^{-1}A^{-1}$
Given, A and B are matrices such that they all invertible and also of same order.
$(AB)^{-1}=B^{-1}A^{-1}$