The second order derivative of $x^3$ log x is :

$x(5+6log\, x)$ $x(2+3log\, x)$ $5x+6log x$ $3x+6log x$

$x(5+6log\, x)$

The correct answer is Option (1) → $x(5+6log\, x)$ $y=x^3\log x$ $\frac{dy}{dx}=3x^2\log x+x^2$ so $\frac{d^2y}{dx^2}=6x\log x+3x+2x$ $=x(5+6\log x)$