The LCM of two numbers is 168 and their HCF is 12. If the difference between the numbers is 60, what is the sum of the numbers?
Answer & explanation
Correct answer: option 3
⇒ (Product of two other factors) × HCF = LCM
⇒ (a × b) × 12 = 168
⇒ (a × b) = 14
So a and b = 7 and 2
Therefore, numbers are:
= (a × HCF), (b × HCF)
= (7 × 12), (2 × 12) = 84 , 24
ATQ,
Difference = 84 - 24 = 60 (given)
So, Sum of two numbers = 84 + 24 = 108