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-- Mathematics - Section A
Definite Integration
If f(2a - x) = f(x) and $\int_0^af(x)dx=λ$ then $\int_0^{2a}f(x)dx$ is:
$2λ$
$λ$
0
None of these
$I=\int\limits_0^{2a}f(x)dx\int\limits_0^{a}f(x)+f(2a-x)dx=\int\limits_0^{a}2f(x)dx$