The ratio of induced emf in a coil of 50 turns and area A oscillating at frequency 50 Hz to that in a coil of 100 turns and same area oscillating at frequency 100 Hz is :
Answer & explanation
Correct answer: option 1
$ \xi \propto NAB\omega $
$ \Rightarrow \frac{\xi_1}{\xi_2} = \frac{N_1\omega_1}{N_2 \omega_2} = \frac{50\times 50}{100\times 100} = 0.25$