Practicing Success
Order of magnitude of density of uranium nucleus is $\left(m_p=1.67 \times 10^{-27} kg\right)$ |
$10^{20} kg / m^3$ $10^{17} kg / m^3$ $10^{14} kg / m^3$ $10^{11} kg / m^3$ |
$10^{17} kg / m^3$ |
The order of magnitude of mass and volume of uranium nucleus will be $m ≃ A\left(1.67 × 10^{-27} kg\right)$ $V=\frac{4}{3} \pi r^3 \simeq \frac{4}{3} \pi\left[\left(1.25 \times 10^{-15} \mathrm{~m}\right) A^{1 / 3}\right]^3 \simeq\left(8.2 \times 10^{-45} \mathrm{~m}^3\right) \mathrm{A}$ Hence, $\rho=\frac{m}{V}=\frac{A\left(1.67 \times 10^{-27} \mathrm{~kg}\right)}{\left(8.2 \times 10^{-45} \mathrm{~m}^3\right) \mathrm{A}} \simeq 2.0 \times 10^{17} \mathrm{~kg} / \mathrm{m}^3$. |