The value of \(\int_{0}^{\frac{\pi}{2}}\displaystyle \log\left(\frac{4 + 3\sin x}{4 + 3\cos x}\right)dx\) is
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 0
Let
\( \displaystyle I = \int_{0}^{\frac{\pi}{2}}\log\left(\frac{4 + 3\sin x}{4 + 3\cos x}\right)dx \)
By the property \(\int_0^a f(x)\,dx = \int_0^a f(a - x)\,dx\), replace x by \(\frac{\pi}{2} - x\); then sin and cos swap:
\( \displaystyle I = \int_{0}^{\frac{\pi}{2}}\log\left(\frac{4 + 3\cos x}{4 + 3\sin x}\right)dx \)
Since \(\log\frac{q}{p} = -\log\frac{p}{q}\), this integral is −I:
\( I = -I \)
\( 2I = 0 \)
\( I = 0 \)