Half the perimeter of a rectangular field whose length is one more than thrice the width is 29; then its dimension are (width and length respectively) :

7 and 22

The correct answer is Option (1) → 7 and 22

let the width of the rectangle be $w$ and length be $l$.

$l=3w+1$

Perimeter, $P=2(l+w)$

$⇒\frac{P}{2}=l+w=29$

$⇒(3w+1)+w=29$

$⇒4w=28$

$⇒w=7$ and $l=22$