Practicing Success
A body is fired with velocity of magnitude $\sqrt{gR} < V< \sqrt{2gR}$ at an angle of 30° with the radius vector of earth. If at the highest point the speed of the body is v/4, the maximum height attained by the body is equal to where R = radius of earth. (Use the appropriate assumptions) |
v2/8g R $\sqrt{2}R$ None of these |
R |
Conservation of angular momentum of the body about O yields mv (sin 30) R = mv' (R + h) ⇒ $\frac{v}{2} R=\frac{v}{4}(R+h)$ ⇒ h = R. |