Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Units and Measurements

Question:

The dimension of potential difference × length are :

Options:

ML3T-3I-1

MLT-2I-1

ML2T-2I

MLT2I

Correct Answer:

ML3T-3I-1

Explanation:

V = $\frac{\text { work }}{\text { charge }} \times$ length $=\frac{ML^2 T^{-2}}{I \times T} \times L$

= ML3T-3I-1