Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Atoms

Question:

The kinetic energy of the electron in an orbit of radius r in hydrogen atom is (e = electronic charge)

Options:

$\frac{e^2}{r^2}$

$\frac{e^2}{2 r}$

$\frac{e^2}{r}$

$\frac{e^2}{2 r^2}$

Correct Answer:

$\frac{e^2}{2 r}$

Explanation:

Potential energy of electron in $n^{\text {th}}$ orbit of radius r in H-atom $U=-\frac{e^2}{r}$ (in CGS)

∵ K.E. = $\frac{1}{2}|P . E .| \Rightarrow K=\frac{e^2}{2 r}$