Evaluate the integral \(\int_0^Πcosx\,dx=?\)
Answer & explanation
Correct answer: option 2
We have integral \(\int_0^Πcosx\,dx=?\)
⇒ \(\int_0^Πcosx\,dx=(sinx)\) for x = 0 to x= Π
= sin (Π) - sin (0)
= 0 - 0
= 0
Evaluate the integral \(\int_0^Πcosx\,dx=?\)
Correct answer: option 2
We have integral \(\int_0^Πcosx\,dx=?\)
⇒ \(\int_0^Πcosx\,dx=(sinx)\) for x = 0 to x= Π
= sin (Π) - sin (0)
= 0 - 0
= 0