The number of photoelectrons emitted from a metal surface for incident light of frequency v (higher than the threshold frequency $v_0$) is directly proportional to: |
Threshold frequency intensity of light frequency of light $\left(v-v_0\right)$ |
intensity of light |
The correct answer is Option (2) → intensity of light It is directly proportional to intensity of light because the as the intensity increases, energy supplied to free electrons will also increases thereby creating many more photoelectrons. |