Practicing Success
Practicing Success
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If $\frac{a^2+b^2+c^2-1024}{ab-bc-ca}=-2$ and a + b = 5c, where c > 0, then the value of c is _____. |
8 4 12 5 |
8 |
If $\frac{a^2+b^2+c^2-1024}{ab-bc-ca}=-2$ a + b = 5c a2 + b2 + c2 - 1024 = -2ab + 2bc + 2ca = a2 + b2 + c2 + 2ab - 2bc - 2ca = 1024 = (a + b - c)2 = 1024 = a + b - c = 32 Put a + b = 5c = 5c - c = 32 = 4c = 32 c = 8 |
