The probability of not getting 53 Tuesdays in a leap year is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{5}{7}$
No. of days in leap year = 366
No. of perfect weeks = $\frac{366}{7}$
= 52 weeks
2 days remain
let M, T, W, Th, F, Sat, Sun denote days
Last two days can be M T, T W, W Th, Th F, F Sat, Sat Sun, Sun M
So there are 5 cases of not getting 53 Tuesdays
$P=\frac{5}{7}$