Practicing Success
Practicing Success
CUET Preparation Today
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$tan\theta = \theta = \frac{F}{mg}$ $\frac{kq^2}{mgx^2} = \frac{x}{2l}$ $x^3 \propto q^2$ differentiating with respect to time $ 3x^2 \frac{dx}{dt}$ = $ 2q\frac{dq}{dt}$ $x^2.v \propto q \text{ where $\frac{dq}{dt}$ is a constant}$ Since $ q\propto x^\frac{3}{2}$ $ v \propto x^\frac{1}{2}$
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