CUET Preparation Today
The volume of a spherical balloon is increasing at the rate of $6 ~cm^3 / sec$. The rate of change of its surface area when its radius is 4 cm is: |
$6 ~cm^2 / sec$ $4 ~cm^2 / sec$ $12 ~cm^2 / sec$ $3 ~cm^2 / sec$ |
$3 ~cm^2 / sec$ |
The correct answer is Option (4) → $3 ~cm^2 / sec$ |
