When 5396, 6248 and 7739 are divided by the greatest number X, the remainder in each case is Y. Which of the following is true?

X = 3Y

The greatest number which leaves same remainders on dividing a, b, c & d is HCF [(b-a), (c-b), (d-c)]

Now, a, b & C  HCF [(b-a), (c-b)]

= (6248 - 5396), (7739 - 6248)      

= 852,     1491

     ↓           ↓

           ↓

    HCF = 213

Now, X = 213

        Y = \(\frac{5396}{213}\) = (71⇒ remainder)

Now, check option (4) ,  X = 3Y

                                   213 = 3 × 71

                                   213 = 213

Hence, X = 3Y