Two chords AB and CD of a circle are produced to intersect each other at a point P outside the circle. If AB = 7 cm, BP = 4.2 cm and PD = 2.8 cm, then the length of CD is:
Answer & explanation
Correct answer: option 4
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We know that ,
PB × PA = PD × PC
4.2 × ( 4.2 + 7 ) = 2.8 × ( 2.8 + CD )
4.2 × 11.2= 2.8 × ( 2.8 + CD )
47.04 = 7.84 + 2.8 CD
2.8 CD = 39.2
CD = 14 cm