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Two chords AB and CD of a circle are produced to intersect each other at a point P outside the circle. If AB = 7 cm, BP = 4.2 cm and PD = 2.8 cm, then the length of CD is: |
12 cm 14.6 cm 15.8 cm 14 cm |
14 cm |
We know that , PB × PA = PD × PC 4.2 × ( 4.2 + 7 ) = 2.8 × ( 2.8 + CD ) 4.2 × 11.2= 2.8 × ( 2.8 + CD ) 47.04 = 7.84 + 2.8 CD 2.8 CD = 39.2 CD = 14 cm
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