\(\int_{-1}^{2}\frac{|x|}{x}dx=\)

1 -1 2 -2

1

$\int\limits_{-1}^{2}\frac{|x|}{x}dx=\int\limits_{-1}^{0}-1dx+\int\limits_{0}^{2}1dx$ $=-1(0+1)+1(2-0)$ $=2-1=1$