Practicing Success
A proton is moving in a circular path in a magnetic field perpendicular to its plane. It possesses kinetic energy E. If the magnetic field increases to four times and the proton is constrained to move along the same circle then its kinetic energy will be |
4 E 16 E $\frac{E}{2}$ E |
16 E |
The correct answer is Option (2) → 16 E |