Equation of line passing through origin and making $30^\circ, 60^\circ$ and $90^\circ$ with $x, y, z$ axes, respectively is
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $\frac{2x}{\sqrt{3}} = \frac{2y}{1} = \frac{z}{0}$ ##
$\cos \alpha = \cos 30^\circ = \frac{\sqrt{3}}{2}$
$\cos \beta = \cos 60^\circ = \frac{1}{2}$
$\cos \gamma = \cos 90^\circ = 0$
Equation of required line
$\frac{x-0}{\frac{\sqrt{3}}{2}} = \frac{y-0}{\frac{1}{2}} = \frac{z-0}{0}$
$\frac{2x}{\sqrt{3}} = \frac{2y}{1} = \frac{z}{0}$