Two cards are drawn at random from a pack of 52 cards one-by-one without replacement. What is the probability of getting first card red and second card Jack? |
$\frac{1}{26}$ $\frac{1}{52}$ $\frac{25}{102}$ $\frac{1}{13}$ |
$\frac{1}{26}$ |
The correct answer is Option (1) → $\frac{1}{26}$ ## The required probability = P[(The first is a red jack card and the second is a jack card) or (The first is a red non-jack card and the second is a jack card)] $= \frac{2}{52} \times \frac{3}{51} + \frac{24}{52} \times \frac{4}{51} = \frac{1}{26}$ |