Answer & explanation
Correct answer: option 3
$ \nu = \frac{E}{h} = \frac{11\times1.6\times10^{-19}}{6.62\times 10^{-34}}= 2.66\times 10^{15}Hz. $
$\text{It lies in the ultraviolet region}$
Correct answer: option 3
$ \nu = \frac{E}{h} = \frac{11\times1.6\times10^{-19}}{6.62\times 10^{-34}}= 2.66\times 10^{15}Hz. $
$\text{It lies in the ultraviolet region}$