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The mass of iron rod is 80 gm and its magnetic moment is $10A.m^2$. If the density of iron is 8 gm/cc, then the value of intensity of magnetization will be |
$10^6$ A/m 3000 A/m $10^5$ A/m 1 A/m |
$10^6$ A/m |
$\text{Volume of iron rod is } = \frac{M}{D} = 10cc = 10\times 10^{-6} m^3$ $ I = \frac{M}{V} = \frac{10}{10^{-5}} = 10^6A/m$ |
