The mass of iron rod is 80 gm and its magnetic moment is $10A.m^2$. If the density of iron is 8 gm/cc, then the value of intensity of magnetization will be
Answer & explanation
Correct answer: option 1
$\text{Volume of iron rod is } = \frac{M}{D} = 10cc = 10\times 10^{-6} m^3$
$ I = \frac{M}{V} = \frac{10}{10^{-5}} = 10^6A/m$