An unbiased coin is tossed 6 times. The Probability of getting at least one head is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{63}{64}$
P (getting atleast 1 head)
= 1 - P (getting no head)
$1-{^6C}_0×(\frac{1}{2})^0(\frac{1}{2})^6$
$=1-\frac{1}{64}=\frac{63}{64}$