CUET Preparation Today
An unbiased coin is tossed 6 times. The Probability of getting at least one head is : |
$\frac{57}{64}$ $\frac{61}{64}$ $\frac{63}{64}$ $\frac{65}{64}$ |
$\frac{63}{64}$ |
The correct answer is Option (3) → $\frac{63}{64}$ P (getting atleast 1 head) = 1 - P (getting no head) $1-{^6C}_0×(\frac{1}{2})^0(\frac{1}{2})^6$ $=1-\frac{1}{64}=\frac{63}{64}$ |
