A, B and C are in a cycle race of 1500 meters. A cycles twice as fast as B, C cycles $\frac{1}{2}$ as fast as B. C completes the race in 40 minutes. Then, where was B from the finishing line when A finished the race?
Answer & explanation
Correct answer: option 4
ATQ,
Ratio of Speed:
A : B = 2 : 1
B : C = 2 : 1
⇒ A : B : C = 4 : 2 : 1
Note: when time is same, then ratio of speed is directly proportional to distance
Therefore, Distance Ratio:
⇒ A : B : C = 4 : 2 : 1
A cycles = 4R = 1500 m
1R = 375,
then B cycles = 2R = 2 × 375 = 750 m
Therefore, when A finish the 1500m race, that time B will be at 750 m from the finishing line.
Alternate:
Speed ratio = Distance ratio:
A : B = 2 : 1
It means B cycles half of A, therefore, when A cycles 1500m at that time B cycles 750m.
Hence, when A finish the 1500m race, that time B will be at 750 m from the finishing line.