Find the value of x, if $21^{\sqrt{x}}+2

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

Find the value of x, if $21^{\sqrt{x}}+20^{\sqrt{x}} = 29^{\sqrt{x}}$.

Options:

Correct Answer:

Explanation:

Using Pythagoras theorem

a² + b² = c²

$21^{\sqrt{x}}+20^{\sqrt{x}} = 29^{\sqrt{x}}$

Compare the whole equation a² + b² = c²

So √x = 2

x = 4

21² + 20² = 29²

441 + 400 = 841

841 = 841

So x = 4 satisfy this equation