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CUET
-- Mathematics - Section A
Definite Integration
$\int\limits_2^3|2x-1|dx$ =
4
5
6
8
$I=\int\limits_2^3|2x-1|dx$ for $x≥\frac{1}{2}|2x-1|=2x-1$
$=\int\limits_2^3 2x-1dx$ from 2 → 3 $|2x-1|=2x-1$
$=[x^2-x]_2^3=3^2-3-2^2+2$
$=9-3-4+2$
$=11-7=4$
