What is the relation between phase difference $(\Delta \theta)$ and path difference $(\Delta x)$?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\Delta \theta=\frac{2 \pi}{\lambda} \Delta x$
The relation between the phase difference $(Δθ)$ and the path difference $(Δx)$ is -
$Δθ=\frac{2 \pi}{\lambda} \Delta x$ [λ = Wavelength of the waves]