CUET Preparation Today
The slope of normal to the curve $y=f(x)$ is m, then : |
$m=-\frac{dy}{dx}$ $m=\frac{dy}{dx}$ $m=\frac{dx}{dy}$ $m=-\frac{dx}{dy}$ |
$m=-\frac{dx}{dy}$ |
The correct answer is Option (4) → $m=-\frac{dx}{dy}$ Slope of tangent = $n=\frac{dy}{dx}$ we know that tangent ⊥ normal $⇒mn=-1$ so $m=-\frac{1}{n}=-\frac{dx}{dy}$ |
