A block of mass m is placed on a smooth inclined wedge ABC of inclination \(\theta\) as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and \(\theta\) for the block to remain stationary on the wedge is : 

a = g Tan \(\theta\)

N sin \(\theta\) = ma 

N cos \(\theta\) = mg

tan \(\theta\) = g tan \(\theta\)