If the binding energy of the deutrium is 2.23 MeV. The mass defect given in a.m.u. is
Answer & explanation
Correct answer: option 4
Mass defect $\Delta m=\frac{2.23}{931}$ = 0.0024.
If the binding energy of the deutrium is 2.23 MeV. The mass defect given in a.m.u. is
Correct answer: option 4
Mass defect $\Delta m=\frac{2.23}{931}$ = 0.0024.