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In triangle of ABC, the bisector of angle BAC cuts the side BC at D. If AB = 10cm, and AC = 14 cm, then what is BD : BC ? |
10 : 7 5 : 7 7 : 5 7 : 10 |
5 : 7 |
According to the concept, \(\frac{AB}{AC}\) = \(\frac{BD}{DC}\) ⇒ \(\frac{10}{14}\) = \(\frac{BD}{DC}\) ⇒ \(\frac{5}{7}\) = \(\frac{BD}{DC}\) So, BD : DC = 5 : 7 Therefore, the answer is 5 : 7 |
