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In a common emitter transistor amplifier current gain is 9 and resistance gain is 20. The voltage gain will be: |
9 × 20 $\frac{9}{20}$ $\frac{20}{9}$ 29 |
9 × 20 |
The correct answer is Option (1) → 9 × 20 The voltage gain ($A_v$) is - $A_v=A_i×A_r$ $=9×20$ $=180$ |
