Swati throws a die twice. What is the probability that she throws at least one six?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → \(\displaystyle\frac{11}{36}\)
“At least one six” is easiest found through its opposite event, no six at all: P(at least one six) = 1 − P(no six).
No six in one throw: \(\displaystyle\frac{5}{6}\)
No six in both throws: \(\displaystyle\frac{5}{6}\times\frac{5}{6}=\frac{25}{36}\)
At least one six: \(\displaystyle 1-\frac{25}{36}=\frac{11}{36}\)