Swati throws a die twice. What is the probability that she throws atleast one six?
Answer & explanation
Correct answer: option 3
Probability = \(\frac{Favorable \; outcomes}{Total \; outcomes}\)
Total number of possible outcomes = 62 = 36
Favorable outcomes = (1,6), (2,6), (3,6), (4,6), (5,6), (6,6), (6,1), (6,2), (6,3), (6,4), (6,5) = 11
So, the probability that she throws atleast one six = \(\frac{11}{36}\)