Swati throws a die twice. What is the probability that she throws atleast one six?

$\frac{1}{36}$ $\frac{1}{4}$ $\frac{11}{36}$ $\frac{35}{36}$

$\frac{11}{36}$

Probability = \(\frac{Favorable \; outcomes}{Total \; outcomes}\) Total number of possible outcomes = 62 = 36 Favorable outcomes = (1,6), (2,6), (3,6), (4,6), (5,6), (6,6), (6,1), (6,2), (6,3), (6,4), (6,5) = 11 So, the probability that she throws atleast one six = \(\frac{11}{36}\)