Three persons A, B and C donate 10%, 7% and 9% respectively of their monthly salaries to a charitable trust. Monthly salaries of A and B are equal and the difference between the donations of A and B is ₹900. If the total donation by A and B is ₹600 more than that of C, then what is the monthly salary (in ₹) of C?
Answer & explanation
Correct answer: option 3
10% = \(\frac{1}{10}\) , 7% = \(\frac{7}{100}\) , 9% = \(\frac{9}{100}\)
Let Salary of A = Salary of B = 100a , salary of C = 100b
Donated amount of A = 100a × \(\frac{1}{10}\) = 10a
Donated amount of B = (100a × \(\frac{7}{100}\) = 7a
Donated amount of C = 100b × \(\frac{9}{100}\) = 9b
ATQ,
3a = 900
a = 300
Total donation of A and B = 17a
17 × 300 = 5100
The total donation by A and B is Rs. 600 more than that of C
5100 – 9b = 600
b = 500
Monthly salary of C = 100b = 100 × 500
Rs. 50000