If $ x = 1 + \sqrt{2}$, then find the value of $\sqrt{x} +(\frac{1}{\sqrt{x}})$.
Answer & explanation
Correct answer: option 2
If $ x = 1 + \sqrt{2}$,
then find the value of $\sqrt{x} +(\frac{1}{\sqrt{x}})$
If $ x = 1 + \sqrt{2}$
then, x = 2.41 ( because $\sqrt{2}$ = 1.41 )
$\sqrt{x} +(\frac{1}{\sqrt{x}})$ = \(\frac{x + 1}{\sqrt{x}}\)
= \(\frac{2.41 + 1}{2.41}\) = \(\frac{3.41 }{1.55}\) = 2.1973