If $x+\frac{1}{x}= 2 cos θ$, then $x^3 +\frac{1}{x^3}=$?
Answer & explanation
Correct answer: option 3
If $x+\frac{1}{x}= 2 cos θ$,
then $x^3 +\frac{1}{x^3}=$?
Put cosθ = 0o
cos0o = 1
then,
$x+\frac{1}{x}= 2$
$x^3 +\frac{1}{x^3}=$ 23 - 2 × 3 = 2
Satisfy from the options = 2 cos 3θ = 2cos0o = 2 satisfied.
So the value of $x^3 +\frac{1}{x^3}$ = 2 cos 3θ