Practicing Success
Practicing Success
CUET Preparation Today
The HCF of \(\frac{2}{3}\) , \(\frac{4}{5}\)&\(\frac{7}{8}\) is : |
\(\frac{2}{120}\) \(\frac{1}{120}\) \(\frac{7}{120}\) \(\frac{7}{60}\) |
\(\frac{1}{120}\) |
HCF of \(\frac{2}{3}\) , \(\frac{4}{5}\)&\(\frac{7}{8}\) = \(\frac{HCF \; of \; numerator}{LCM \; of \; denominator}\) HCF of numerator= 1 LCM of denominator ( 3 × 5 × 8 ) = 120 HCF of \(\frac{2}{3}\) , \(\frac{4}{5}\)&\(\frac{7}{8}\) = \(\frac{1}{120}\) |
