Practicing Success
Practicing Success
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| If the position vector \(\vec{a}\) of a point \((12,n)\) is such that \(|\vec{a}|=13\), then the value of \(n\) is |
\(\pm 25\) \(\pm 12\) \(\pm 7\) \(\pm 5\) |
| \(\pm 5\) |
| \(\begin{aligned}\text{Given , }|\vec{a}|&=13\\ |12\hat{i}+n\hat{j}|&=13\\ \sqrt{12^{2}+n^{2}}&=13\\ n^{2}&=169-144=25\\ n&=\pm 5\end{aligned}\) |
