Constraints for a LPP are : $x+2y≤6,

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Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Linear Programming

Question:

Constraints for a LPP are :

$x+2y≤6, 3x+2y ≤ 12, x≥0, y ≥ 0$

Then corner point in the feasible region which is not on any of the axes is :

Options:

(3, 2)

$(\frac{7}{2}, 2)$

$(3, \frac{3}{2})$

$(\frac{7}{2}, \frac{3}{2})$

Correct Answer:

$(3, \frac{3}{2})$

Explanation:

The correct answer is Option (3) → $(3, \frac{3}{2})$

$x+2y=6$ ...(1)

$2y+3x=12$ ...(2)

Solving (1) and (2),

$x=3$ and $y=\frac{3}{2}$