Constraints for a LPP are :
$x+2y≤6, 3x+2y ≤ 12, x≥0, y ≥ 0$
Then corner point in the feasible region which is not on any of the axes is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $(3, \frac{3}{2})$
$x+2y=6$ ...(1)
$2y+3x=12$ ...(2)
Solving (1) and (2),
$x=3$ and $y=\frac{3}{2}$