Practicing Success
Magnetic moment of a divalent ion in aqueous solution with atomic number 25 is: |
\(\sqrt{5(5+1)}\) BM \(\sqrt{5(5+2)}\) BM \(\sqrt{7(7+2)}\) BM 2\(\sqrt{5(5+1)}\) BM |
\(\sqrt{5(5+2)}\) BM |
25Mn: [Ar]4s23d5 Mn2+: [Ar]3d5
so, there are five unpaired electrons. n= 5 Magnetic moment, μ = \(\sqrt{n(n+2)}\) = \(\sqrt{5(5+2)}\) BM |